What will be the pressure exerted by a mixture of `3.2 g` of methane and `4.4g` of carbon dixide contained in a `9 dm^(3)` flask at `27^(@)C` ? .

Answer

`8.31xx10^(4)Pa`

Explanation

`"Moles of "CH_(4)=(3.2)/(16)=0.2`
`p_((CH_(4)))=(nRT)/(V)=(0.2xx8.314xx300)/(9xx10^(-3))`
`=5.54xx10^(4)Pa`
`"Moles of "CO_(2)=(4.4)/(44)=0.1`
`p_((CO_(2)))=(0.1xx8.314xx300)/(9xx10^(-3))=2.77xx10^(4)Pa`
`"Total pressure"=5.54xx10^(4)Pa+2.77xx10^(4)Pa`
`=8.31xx10^(4)Pa`