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Compare the rates of diffusion of '^(23...

Compare the rates of diffusion of ` '^(235)UF_(6)` and ` '^(238)UF_(6)`

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Verified by Experts

The correct Answer is:
1.004:1
`(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))`
`M_(1)="Mol.wt. of "^(235)UF_(6)=235+6xx19=349`
`M_(2)="Mol. Wt. of "^(238)UF_(6)=238+6xx19=352`
`(r(""^(235)UF_(6)))/(r(""^(238)UF_(6)))=sqrt((352)/(349))=1.004`
`therefore" "r(""^(235)UF_(6)):r(""^(238)UF_(6))=1.004:1.`
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