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At 26.7^(@)C, the vapour density of a ga...

At `26.7^(@)C`, the vapour density of a gaseous mixture containing `NO_(2) and N_(2)O_(4)` is 38.31. calculate the number of moles of `NO_(2)` in 100g of that mixture.

Text Solution

Verified by Experts

Molecular weight of mixture
`=2xx"Vapour density"`
`=2xx38.3=76.6`
Let the mixture contains x g of `NO_(2)` and `(100-x)g" of "N_(2)O_(4)`
`"Moles of "NO_(2)=(x)/(46)`
`"Moles of "N_(2)O_(4)=(100-x)/(92)`
`"Moles of mixture"=(100)/(76.6)`
`"Now, moles of "NO_(2)" and "N_(2)O_(4)="Moles of mixture"`
`(x)/(46)+(100-x)/(92)=(100)/(76.6)`
`2x+100-x=(100xx92)/(76.6)`
`100+x=120.1`
`therefore" "x=120.1-100=20.1`
`therefore" Moles of "NO_(2)=(20.1)/(46)=0.437`
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