Calculate the total number of electrons present `1.4` g of dinitrogen gas.

Explanation

`"Moles of dinitrogen"=(1.4)/(28)=0.05`
`"No. of molecules of dinitrogen"=0.05xx6.02xx10^(23)`
`=3.011xx10^(22)`
`"No. of electrons in one molecule of "N_(2)=14`
`therefore" No. of electrons in 1.4 g of "N_(2)=3.011xx10^(22)xx14`
`=4.2154 xx10^(23)`