`2.9 g` of a gas at `95^(@) C` occupied the same volume as `0.184 g` of hydrogen at `17^(@)C` at same pressure What is the molar mass of the gas ? .

Explanation

Let molar mass of gas is M.
`"Moles of gas"=(2.9)/(M), T=273+95=368K`
`"Volume og gas, V"=(nRT)/(p)`
`=(2.9xxRxx368)/(Mxxp)`
`"Moles of dihydrogen"=(0.184)/(2)=0.092,`
`T=273+17=290K`
`"Volume of dihydrogen"=(0.092xxRxx290)/(p)`
`"Volume of gas"="Volume of dihydrogen"`
`" at same pressure, p"`
`(2.9xxRxx368)/(M)=0.092xxRxx290`
`therefore" "M=(2.9xx368)/(0.092xx290)=40.`