`Lil_3` is less stable than `CsI_3`. Why?

Explanation

To understand why \( \text{LiI}_3 \) is less stable than \( \text{CsI}_3 \), we can break down the reasoning into several steps:

### Step-by-Step Solution:

1. **Identify the Compounds**: We are comparing two compounds: lithium triiodide (\( \text{LiI}_3 \)) and cesium triiodide (\( \text{CsI}_3 \)).

2. **Understand the Anion Size**: The anion in both compounds is \( \text{I}_3^- \), which is a large anion composed of three iodine atoms. The size of this anion is significant because it affects how well it can fit with the cation in the crystal lattice.

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