हल कीजिए : ` 2 sin^(2) theta + sin^(2) 2 theta =2`

2sin^(2)theta+sin^(2)2 theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

sin^(4)theta+sin^(2)theta cos^(2)theta=

Prove each of the following identities : (sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta) = (2) /((sin^(2) theta - cos^(2) theta)) = (2) /((2sin^(2) theta -1))

I : cos^2 theta + cos^(2) (60^@ + theta ) + cos^(2) (60^@ - theta ) = 3//2 II : sin^(2) theta + sin^(2)(60^(@) + theta ) + sin^(2)(60^(@) - theta ) =3//2

sin2 theta=2sin theta cos theta

The roots of the equation |(3x^(2),x^(2) + x cos theta + cos^(2) theta ,x^(2) + x sin theta + sin^(2) theta),(x^(2) + x cos theta + cos^(2) theta,3 cos^(2) theta,1 + (sin 2 theta)/(2)),(x^(2) + x sin theta + sin^(2) theta,1 + (sin 2 theta)/(2),3 sin^(2) theta)| = 0