In the third of vibrations of the string, the distance between extreme end nodes is 2m, then the position of the nodes from the ends will be

In a pipe open at both the ends the distance between node and antinode is

Assertion : In the nth normal mode of vibration of a string, there are (n+1) nodes and n antinodes. Reason : This is because both the ends of the string are fixed and from nodes.

Taking the open end of tube as y =0 position of pressure nodes will be .

Compute the distance between anti-node and neighbouring node .

When a stretched string of length L vibrating in a particular mode, the distance between two nodes on the string is l . The sound produced in this mode of vibration constitutes the nth overtone of the fundamental frequency of the string.

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.