A block of mass "2kg" is placed on the floor.If "a],[" force of "2.8N" is applied on the block parallel at angle of "30" degree from horizontal,then acceleration of block is `(take "g=10m/s^(2)" )`

A block of mass 2 kg is placed on the floor The coefficient of static friction is 0.4. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and the floor (take g =10ms^-2) is

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A block of mass 2 kg is placed on the floor . The coefficient of static friction is 0.4 . If a force of 2.8 N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = 10 m//s^(2) )

A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is 0.2 . If a force of 20 N is applied to the block at angle of 30^(@) with the horizontal plane , what is the force of friction on the block ? (Take g = 10 m//s^(2) )

A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))

A block of mass 2 kg is placed on the floor (mu=0.4) . A horizontal force of 7 N is applied on the block. The force of friction between the block & floor is f_(s) . Find the f_(s) .

A block of mass 2kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 2.5N is applied on the block . Calculate the force of friction between the block and the floor.

A block of mass 2 kg is placed on the floor. The coefficient of static friction it 0.4 . A force F of 2.5 N is applied on the block, as shown. calculate the force of friction between the block and the floor. (g=9.8m//s^(2)) .