Home
Class 12
CHEMISTRY
To a 10mL, 1M aqueous solution of Br(2),...

To a 10mL, 1M aqueous solution of `Br_(2)`, excess of NaOH is added so that all `Br_(2)` is disproportionated to `Br^(-)` and `BrO_(3)^(-)`. The resulting solution is free from `Br^(-)`, by extraction and excess of `OH^(-)` neutralised by acidifying the solution. The resulting solution is suffcient to react with 2 g of impure `CaC_(2)O_(4)`(M= 128g/mol) sample. The % purity of oxalate sample is :

Promotional Banner

Similar Questions

Explore conceptually related problems

To a 10mL, 1M aqueous solution of Br_2, excess of NaOH is added so that all Br_2 is disproportionated to Br^- and BrO_3^- . The resulting solution is free from Br^- , by extraction and excess of OH^- neutralised by acidifying the solution. The resulting solution is sufficient to react with 2g of impure Ca C_2 O_4 (M=128 g/mol) sample. The % purity of oxalate sample is :

10 mL of 1.0 M aqueous solution of Br_(2) is added to excess of NaOH in order to disproportionate quantitatively to Br^(-) " and " BrO_(3)^(-) . The resulting soluting is made free from Br^(-) ion by extraction and excess of OH^(-) neutralized by acidifying the solution. This solution requires 1.5 g of an impure CaC_(2)O_(4) sample for complete redox change . Calculate % purity of CaC_(2)O_(4) sample.

If 100 mL of 1NH_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

A sample of NaOH weighing 0.4 g. is added to 100 ml of 0.1N H_2SO_4 solution. The nature of the resulting solution is

A sample of Na_(2)CO_(3).H_(2)O weighing 0.62 g is added to 10 ml of 0.1 N H_(2)SO_(4) solution . The resulting solution will be