`(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=`

(sin theta)/(cos(3theta))+(sin(3theta))/(cos(9theta))+(sin(9theta))/(cos(27theta))+(sin(27theta))/(cos(81theta))=

(sin theta)/(cos(3theta))+(sin(3theta))/(cos(9theta))+(sin(9theta))/(cos(27theta))+(sin(27theta))/(cos(81theta))=

Prove that sintheta/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)=1/2(tan27theta-tantheta)

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)

Prove that : sintheta/cos(3theta)+sin(3theta)/cos(9theta)+sin(9theta)/cos(27theta)=1/2(tan(27theta)-tan(theta))

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=lambda[(Tan mu theta)-Tan theta]" then "mu-50 lambda =