`log(logx)+log(logx^3-2)=0`;where base of log is 10 everywhere.

log(log x)+log(log x^(3)-2)=0; where base of log is 10 everywhere.

Solve for x, (a) (log_(10)(x-3))/(log_(10)(x^(2)-21))=(1)/(2),(b)log(log x)+log(log x^(3)-2)=0; where base of log is 10 everywhere.

Solve for x: a) (log_(10)(x-3))/(log_(10)(x^(2)-21)) = 1/2 b) log(log x)+log(logx^(3)-2)= 0, where base of log is 10. c) log_(x)2. log_(2x)2 = log_(4x)2 d) 5^(logx)+5x^(log5)=3(a gt 0), where base of log is 3. e) If 9^(1+logx)-3^(1+logx)-210=0 , where base of log is 3.

9^(1+logx)-3^(1+logx)-210=0 where the base of log is 10

9^(1+logx)-3^(1+logx)-210=0 where the base of log is 10

d/(dx) [log(logx)] =

d/(dx) log(logx) = ?

d/(dx) log(logx) = ?

d/(dx) [log(logx)] =

int(log(logx))/(x.logx)dx=