The axis of a parabola is along the line y = x and the distance of its vertex from origin is `sqrt2` and that from its focus is `2sqrt2`. If vertex and focus both lie in the first quadrant, then the equation of the parabola is

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt(2) and 2sqrt(2) respectively.If vertex and focus both lie in the first quadrant,then the equation of the parabola is:

The axis of a parabola is along the line y = x and its vertex and focus are in the first quadrant at distances sqrt2,2sqrt2 respectively, from the origin. The equation of the parabola, is

If the vertex and focus of a parabola are (2,1) and (1,-1) then its equation is

If the vertex and focus of a parabola are (2,1) and (1,-1) then its equation is

A parabola is drawn with focus at (3,4) and vertex at the focus of the parabola y^2-12x-4y+4=0 . The equation of the parabola is