The centre of mass of a system of two particles of masses `m_(1)` and `m_(2)` is at a distance `d_(1)` from `m_(1)` and at a distance `d_(2)` from mass `m_(2)` such

The centre of mass of a system of two particle of masses m_1 and m_2 is at a distance d_1 from m_1 and at a distance d_2 from mass m_2 such that.

The position of centre of mass of a system consisting of two particles of masses m_(1) and m_(2) seperated by a distance L apart , from m_(1) will be :

Calculate the position of centre of mass of a system consisting of two particles of masses m_1 and m_2 separated by a distance L apar, from m_1?

If vec(R)_(CM) is the position of the centre of mass of a system of two particles of masses m_(1) and m_(2) then vec(R)_(CM) is given by :

Position vector of centre of two particles of masses m_(1) and m_(2) whose position vectors r_(1) and r_(2) then r_(cm) ?

There are two masses m_(1) and m_(2) , placed at a distance l apart, let the centre of mass of this system is at a point named C . If m_(1) is displaced by l_(1) towards C and m_(2) is displaced by l_(2) away from C , find the distance from (C) where the new centre of mass will be located.

The centre of masses of three particles of mass m_(1) = m_(2)=m_3 = 1 kg at the corners of an equilateral triangle of side 1 m will be -

Two bodies of masses m_(1) and m_(2) are separated by a distance R. The distance of the centre of mass of the bodies from the mass m_(1) is

Consider a system of two particles having masses m_(1) and m_(2) . If the particle of mass m_(1) is pushed towards the centre of mass of particles through a distance d , by what distance would the particle of mass m_(2) move so as to keep the mass centre of particles at the original position?