`tan A . Sin A+ cos A=secA`

Prove that : (1 + cot A + tan A) (sin A — cos A) = sin A tan A — cot A cos A.

Prove that : (1 + cot A + tan A) (sin A — cos A) = sin A tan A — cot A cos A.

Prove that :(1+cot A+tan A)(sin A cos A)=sin A tan A cot A cos A

(1 + cot A + tan A) (sin A-cos A) = sin A tan A-cot A cos A

(cos A) / (1-tan A) + (sin A) / (1-cot A) = sin A + cos A

Prove that (sec A-cosec A)(1+tan A+cot A)=tan A secA + cotA cosec A

(cos A + sin A )/( cos A - sin A) - (cos A - sin A )/(cos A + sin A ) = 2 tan 2 A.

The value of tan^(4)A + tan^(2)A in terms of secA is

'solve tan ( sin − 1 ( cos ( sin − 1 x ) ) ) tan ( cos − 1 ( sin ( cos − 1 x ) ) ) '

Prove that (i) (sec 8A -1)/(sec 4A -1) =(tan 8A)/(tan 2A) (ii) (cos A+ sin A)/(cos A - sin A)-(cos A-sin A)/(cos A+sin A)=2 tan 2A