The perimeter of the square is 64m. then the side of the square is:

The perimeter of a square is 60x m. Find the side of the square.

The perimeter of a square = 4s Area of a square = s xx s Perimeter of a rectangle = 2 (l + b) Area of a rectangle = l xx b The perimeter of a square = 24 units. The side of a square is

The perimeter of a square is twice the perimeter of a rectangle. If the perimeter of the square is 56 cm and the length of the rectangle is 9 cm, what is the difference between the breadth of the rectangle and the side of the square?

If the area of a rectangular field, whose dimensions are 64 m xx 36 m, is equal to the area of a square field, then the side of the square (in m.) is:

If the perimeter of a square is 50 cm, then its side is

Sum of the areas of two squares is 260 m^(2) . If the difference of their perimeters is 24 m then find the sides of the two squares.

The perimeter of a square is twice the perimeter of a rectangle. If the perimeter of the square is 72 cm and the length of the rectangle is 12 cm. what is the difference between the breadth of the rectangie and the side of the square?