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In a binary solution, the component pres...

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton
The mole fraction of glycerine `C_(3)H_(5)(OH)_(3)` in a solution containing 36 g of water and 46 g of glycerine is :

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In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The molality of pure water is :

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The unit of molarity are

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton 1.57 g of oxalic acid (COOH)_(2)xH_(2)O are dissolved in water and the volume is made upto 250 mL. On titrating 6.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralisation. The value of x is :

Number of moles of solute dissolved in 1000 g. of the solvent is called

When 1 mole of the substance present in 1 L of solution is known as

Semimolar solution contains how many moles of solute in 1L of solution?

A molar solution is one that contains one mole of a solute in

A aqueous solution contains 10 moles of sucrose in 1 kg of solvent. calculate the molality of solution.