Two oxides of metal M have `27.6%` and `30%` oxygen by weight. If the formula of the first oxide is `M_(3)O_(4)` what is the formula of second oxide?

Two oxide of metal M have 27.6% and 30% oxygen by weight. If the formula of the first oxide is M_(3)O_(4) what is the formula of second oxide?

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 50% and 40% metal M respectively. If the formula of the first oxide is MO_(2) , the formula of the second oxide will be

Two oxides of a metal contain 36.4% and 53.4% of oxygen by mass respectively. If the formula of the first oxide is M_(2)O , then that of the second is

Two oxides of a non-metal X contain 50% and 40% of non -metal respectively. If the formula of the first oxide is XO_2 , then the formula of second oxide is