Find `(dy)/(dx)` if `x=cos theta - cos 2 theta`
`and" "y = sin theta - sin 2theta`

Find (dy)/(dx) , " if x " = 2 cos theta - cos 2 theta and y = 2sin theta - sin 2 theta .

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x= 2 cos theta - cos 2theta and y= 2sin theta - sin 2theta.

Find (dy)/(dx) : x=2 cos theta- cos^(2) theta and y=2 sin theta- sin 2theta Show that (dy)/(dx)= -1 " when " theta = (pi)/(2)

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

Find dy/dx if : x= 3 cos theta - 2 cos^3 theta , y= 3 sin theta - 2 sin^3 theta

if x = "cos" theta - "cos" 2 theta, y = "sin" theta - "sin" 2 theta , then dy/dx is