Two balls are thrown horizontally from the top of a tower with velocities `v_(1)` and `v_(2)` in opposite directions at the same time. After how much time the angle between velocities of balls becomes `90^(@)` ?

A ball is thrown horizontally from the top of a tower with a velocity of 40ms-1 .' Take g = 10 ms^2 '

A ball is projected horizontal from the top of a tower with a velocity v_(0) . It will be moving at an angle of 60^(@) with the horizontal after time.

A ball is projected horizontal from the top of a tower with a velocity v_(0) . It will be moving at an angle of 60^(@) with the horizontal after time.

From the top of a tower, two balls are thrown horizontally with velocities u_(1) and u_(2) in opposite directions. If their velocities are perpendicular to each other just before they strike the ground, find the height of tower.

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

From the top of the tower, two balls are thrown horizontally in opposite directions with velocities u_(1) and u_(2) . Find the distacne between the balls at the moment when their velocity vectors becomes mutually perpendicular. (Assume the height of tower very large)