An electron revolves in a circle of radius 0.4 Å with a speed of `10^(5)m//s`. The magnitude of the magnetic field produced at the centre of the circular path due to the motion of the electron in `W//m^(2)` is

An electron revolves in a circle of radius 0.4 A with a speed of 1 0^(6)ms^(-1) in a hydrogen atom. The magnetic field produced at the centre of the orbit due to the motion of the electron (in tesla) is [mu_(0)=4pixx10^(-7)Hm^(-1) , charge on the electron= 1.6xx10^(-19)C]

An electron revolves in a circle of radius 0.4 A^(0) ith a speed of 10^6 ms^(-1) in a hydrogen atom. The magnetic field produced at the centre of the orbit due to motion of the electron, in tesla, is [mu_(0)=4pixx10^(-7)H//m]

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

Arrive at the expression for the magnetic field at the centre of the circular path due to an orbiting electron.

The radius of the first electron orbit of a hydrogen atom is 0.5overset@A . The electron moves in this orbit with a uniform speed of 2.2xx10^6 m/s . What is the magnetic field produced at the centre of the nucleus due to the motion of this electron?

Imagine that an electron revolves around a circle of the radius 5.3xx10^(-11)m with a linear speed of 7.5xx10^4 ms^(-1) in a hydrogen atom. The magnetic field produced at the centre of the circle, due to the electron, is

Imagine that an electron revolves around a circle of the radius 5.3xx10^(-11)m with a linear speed of 7.5xx10^4 ms^(-1) in a hydrogen atom. The magnetic field produced at the centre of the circle, due to the electron, is

The radius of the first electron orbit of a hydrogen atom is 0.5overset(@)A . The electron moves in this orbit with a uniform speed of 2.2xx10^(6)m.s^(-1). What is the magnetic field produced at the centre of the nucleus due to the motion of this electron?