At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl` added to `1 kg` water `(k_(b)=0.52 K mol^(-1)kg)` in order to raise the b.pt. of solution to `100 ^(@)C` is (assume `90%` ionisation of `NaCl`):

To observe an elevation of boiling point at 0.05^@C , the amount of solute (mol.wt =100) to be added to 100g of water (k_b=0.5) is

A sugar solution boils at 101^(@)C . The molality of the sugar solution is (Given, K_(b) = 0.52^(@)C kg mol^(-1) )

Calculate the boiling point of a solution prepared by adding 15.00 g of NaCl to 250 g of water . (K_(b) = 0.512 K kg mol^(-1) and molar mass of NaCl = 58.44 g mol^(-1) )

If Boiling point of water is 100^(@)C . How much gram of NaCl is added in 500 g of water to increase its boiling point of water by approx 1^(@)C.(K_(b))_(H_(2)O)="0.52 K kg/mole".

A solid cube of edge length =25.32 mm of an ionic compound which has NaCl type lattice is added to 1kg of water.The boiling point of this solution is found to be 100.52^@C (assume 100% ionisation of ionic compound).If radius of anion of ionic solid is 200 pm then calculate radius of cation of solid in pm (picometer). ( K_b of water =0.52 K kg "mole"^(-1) ,Avogadro's number, N_A=6xx10^(23),(root3(75))=4.22 )