सिद्ध कीजिए कि ` (cos 2A)/(1+sin2A) = tan (pi/4 -A)`

Prove that: (cos2A)/(1+sin2A) = tan(pi/4-A)

Prove that: (cos2A)/(1+sin2A) = tan(pi/4-A)

(1+sin2A)/(1-sin2A)=tan^(2)((pi)/(4)+A)

Prove that : ("cos" 2A)/(1+"sin" 2A)="tan"(pi/(4)-A)

Prove that : (1+sin 2A)/(cos 2A) = (cos A + sin A)/(cos A - sin A) = tan (pi/4 + A)

(1 + sin2A) / (cos2A) = (cos A + sin A) / (cos A-sin A) = tan ((pi) / (4) +1)

If sin 4 A - cos 2A = cos 4A - sin 2A, (0 lt A lt (pi)/(4)) then the value of tan 4A is

If sin 4 A - cos 2 A = cos 4 A - sin 2A (0 lt Alt (pi)/( 4)) then the value of tan 4A is

यदि triangleABC में (If इन triangleABC), a = (1)/(sqrt(6)-sqrt(2)), b = (1)/(sqrt(6)+sqrt(2)), C = 60^(@) तो सिद्ध कीजिए कि (Prove that) c = (sqrt(4))/(2) .

सिद्ध कीजिए कि |vecA xx vecB|^(2) + |vecA * vecB|^(2) = (AB)^(2).