A compound contains 7 carbon atoms, 2 oxygen atoms and `1.0 xx 10^(-23)` gmof other elements. The molecular mass of compound is : `(N_(A) = 6 xx 10^(23))`

Each molecular of a compound contains 5 carbon atoms, 8 hydrogen atoms and 4 xx 10^(-23) gm of other element. The molecular mass of compounds is (N_(A) = 6 xx 10^(23))

Each molecular of a compound contains 5 carbon atoms, 8 hydrogen atoms and 4 xx 10^(-23) gm of other element. The molecular mass of compounds is (N_(A) = 6 xx 10^(23))

A molecule of a compound have 13 carbon atoms, 12 hydrogen atom, 3 oxygen atoms and 3.02 times 10^(-23) gm of other element. Find the molecular wt. of compound.

One atom of an element X weighs 6 xx 10^(-23) gm . Number of moles of atoms in 3.6 kg of sample of X will be : (N_(A) = 6 xx 10^(23))

One atom of an element X weighs 6 xx 10^(-23) gm . Number of moles of atoms in 3.6 kg of sample of X will be : (N_(A) = 6 xx 10^(23))

A box contains 12xx10^(22) number of oxygen atoms. Find moles of O-atoms? (N_(A)=6xx10^(23))

30 g of element x contains 18.069 xx 10^(23) atoms of x. Calculate gram-molecular mass of x_(2)