A projectile takes off with an initial velocity of `10 m//s` at an angle of elevation of `45^@`. It is just able to clear two hurdles of height 2 m each, separated from each other by a distance d. Calculate d. At what distance from the point of projection is the first hurdle placed? Take `g = 10m//s^2`.

A projectile takes off with an initial velocity of 50m//s at an angle of 37^(@) with horizontal, It is just able to clear two hurdles of height 25m each, separated from each other by a distance d Calculate d .

A projectile takes off with an initial velocity of 50m//s at an angle of 37^(@) with horizontal, It is just able to clear two hurdles of height 25m each, separated from each other by a distance d Calculate d .

A projectile takes off with an initial velocity of 50m//s at an angle of 37^(@) with horizontal, It is just able to clear two hurdles of height 25m each, separated from each other by a distance d Calculate d .

A ball projected with a velocity of 10m//s at angle of 30^(@) with horizontal just clears two vertical poles each of height 1m . Find separation between the poles.

An object is projected so that it just clears two walls of height 7.5 m and with separation 50m from each other. If the time of passing between the walls is 2.5s, the range of the projectile will be (g= 10m//s^(2) )

A particle is projected from the ground with some initial velocity making an angle of 45^(@) with the horizontal. It reaches a height of 7.5 m above the ground while it travels a horzontal distance of 10 m from the point of projection . Find the initial speed of projection ( g = 10 m//s^(2) ) .

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .