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D=|[1,3cos theta,1],[sin theta,1,3cos th...

D=|[1,3cos theta,1],[sin theta,1,3cos theta],[1,sin theta,1]|" di "D+1" भénน "[54n..........6

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(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)

cos theta/(1+sin theta)=(1-sin theta)/cos theta

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

((sin theta+cos theta-1)/(sin theta-cos theta+1))(1+sin theta) =

(cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

(1+cos theta+sin theta)/(1+cos theta-sin theta)=(1+sin theta)/(cos theta)

(1 + sin theta-cos theta) / (1 + sin theta + cos theta)