`(sintheta+sin2theta)/(1+costheta+cos2theta)=tantheta`

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

Prove that (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta .

Prove that (frac(sintheta-2sin^3theta)(2cos^3theta-costheta))=tantheta

Prove : (1+sin2theta-cos2theta)/(1+sin2theta+cos2theta)=tantheta

Prove the following (sintheta-2sin^3theta) /(2cos^3theta-costheta) =tantheta

Given that 1-costheta=2sin^2(theta/2) and 1+costheta=2cos^2(theta/2) prove that (1+sintheta-costheta)/(1+sintheta+costheta)=tan(theta/2)

Prove the following: (frac(1-cos2theta+sin2theta)(1+cos2theta+sin2theta))=tantheta

For -pi/2

Prove that (1+sintheta-cos theta)/(1+sin theta+costheta)=tantheta//2

For -(pi)/(2)lttheta(pi)/(2),(sintheta+sin2theta)/(1+costheta+cos2theta) lies in the interval