समीकरण हो हल कीजिए: `|z+1|=z+2(1+i)`

निम्न समीकरण को हल कीजिए - tan^(-1)(x-1)+tan^(-1)(x)+tan^(-1)(x+1)=tan^(-1) 3 x

If z_(1)=5-7i and z_(2)=7-9i , verify: (i) |-z_(1)|=|z_(1)| (ii) |z_(1)z_(2)|=|z_(1)||z_(2)|

if z_(1)=3+4i and z_(2)=12-5i , verify: (i) |-z_(1)|=|z_(1)| (ii) |z_(1)+z_(2)|lt|z_(1)|+|z_(2)| (iii) |z_(1)z_(2)|=|z_(1)||z_(2)| .

If z_1 = 3 + 4i and z_2=12 -5i , verify : |z_1 z_2|= |z_1| |z_2| .

If z_1 = 5 + 7i and z_2= 7 - 9i ,verify : |z_1/z_2|= (|z_1|)/ (|z_2|) .

If z_1, z_2 and z_3 , are the vertices of an equilateral triangle ABC such that |z_1 -i| = |z_2 -i| = |z_3 -i| .then |z_1 +z_2+ z_3| equals:

If z_1, z_2 and z_3 , are the vertices of an equilateral triangle ABC such that |z_1 -i| = |z_2 -i| = |z_3 -i| .then |z_1 +z_2+ z_3| equals:

If z_(1),z_(2),z_(3) are the vertices of an equilational triangle ABC such that |z_(1)-i|=|z_(2)- i| = |z_(3)-i|, then |z_(1)+z_(2)+z_(3)| equals to

If z_(1),z_(2),z_(3) are the vertices of an equilational triangle ABC such that |z_(1)-i|=|z_(2)- i| = |z_(3)-i|, then |z_(1)+z_(2)+z_(3)| equals to