A force `F=Kx^(2)` acts on a particle at an angle of `60°` with the x–axis. the work done in displacing the particle from `x_(1)` to `x_(2)` will be –

A force F=-(K)/(x^(2))(xne0) acts on a particle along the X-axis . Find the work done by the force in displacing the particale from x = +a to x = + 2a. Take K as a positive constant .

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = 2a . Here, k is a positive constant.

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = 2a . Here, k is a positive constant.

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = + 2a . Where, k is a positive constant.

A force F acting on a particle varies with the position x as shown in the graph. Find the work done by the force in displacing the particle from x =-a to x = +2a . .

A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from

A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from