" (i) "sqrt(ab)=sqrt(a)sqrt(b)

If sqrt(ab)=sqrt(a)sqrt(b) and a<0 , find arg(b+ai)

If sqrt(ab)=sqrt(a)sqrt(b) and a<0, find arg(b+ai)

The conjugate surd of sqrt(a)+b is sqrt(a)-b b- "sqrt(a) sqrt(a)+sqrt(b) sqrt(a)-sqrt(b)

Let a,b in R.sqrt(a)sqrt(b)=sqrt(ab) is not true if

If sqrt(a)>sqrt(b)>sqrt(c)>sqrt(d) where a,b,c and d are consecutive natural numbers then which of the following is correct (1)sqrt(a)-sqrt(b)>sqrt(c)-sqrt(d)(2)sqrt(c)-sqrt(d)>sqrt(a)-sqrt(b)(3)sqrt(a)-sqrt(c)>sqrt(b)-sqrt(d)(4)sqrt(c)-sqrt(d)=sqrt(a)-sqrt(b)

Evaluate : ( sqrt(a) + sqrt(b) ) ( sqrt(a) - sqrt(b) )

If a and b are positive natural numbers (sqrt(a)+sqrt(b))(sqrt(c)+sqrt(d))=sqrt(ac)+sqrt(ad)+sqrt(bc)+sqrt(bd)

Show that : sqrt( a/b ) = sqrt(a)/ sqrt( b )