cos x+sin x=cos2x+sin2x

Solve the following: cos x+sin x=cos 2x+sin 2x

3-2cos x-4sin x-cos2x+sin2x=0

The value of (2(sin2x+2cos^(2)x-1))/(cos x sin x cos3x+sin3x) is

Solve the following trigonometric equation : cos x + sin x = cos 2x+ sin 2x .

Evaluate: int(cos x-sin x)/(cos x+sin x)(2+2sin2x)dx

If (x)=(cos x+i sin x)(cos2x+i sin2x)(cos3x+i sin3x)...(cos nx+i sin nx)= and f(1)=1, then f'(1) is equal to

If f(x)=(cos x+i sin x)(cos2x+i sin2x)(cos3x+i sin3x)......(cos nx+i sin n and f(1)=1, then f^(11) is equal to (a) (n(n+1))/(2) (b) {(n(n+1))/(2)}^(2)(C)-{(n(n+1))/(2)}^(2) (d) none of these

If quad f(x)=(cos x+i sin x)(cos2x+i sin2x)(cos3x+i sin3x)cos nx+i sin nx and f(1)=1, then f(1) is equal to (n(n+1))/(2) (b) {(n(n+1))/(2)}^(2)(c)-{(n(n+1))/(2)}^(2) (d) none of these

If 1+sin x sin2x=cos x cos2x, then x=

cos2x-sin2x>=0