In the relation `( dy)/( dt) = 2 omega sin ( omega t + phi_(0))`, the dimensional formula for ` omega t + phi_(0)` is

In the equation y = A sin (omega t - kx), obtain the dimensional formula of omega and k. Given x is distnace and t is time.

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

Three sinusoidal displacements are applied in X-direction to a point mass in such a way that total displacement is zero and the mass comes to rest. What are the values of B and phi if the equations are x_(1) (t) = A sin 2 omega t x_(2) (t) = A sin (2 omega t + (4pi)/(3)) x_(3) (t) = B sin (2 omega t + phi)

Check the correctness of the equation : y = a "sin" (omega t + phi) , where y = displacement , a = amplitude , omega = angular frequency and phi is an angle .

If i_(1) = i_(0) sin (omega t), i_(2) = i_(0_(2)) sin (omega t + phi) , then i_(3) =