(dy)/(dx)=(y^(2))/(xy-x^(2))

The equation of the curve satisfying (dy)/(dx)=(y^(2)-2xy-x^(2))/(y^(2)+2xy-x^(2)) and passing through (1,-1) is:

Solve (dy)/(dx) =(y^(2)-2xy)/(x^(2)-xy)

Solve the differential equations: (dy)/(dx)=(x^2+y^2)/(xy+x^2)

Solve the following differential equations (dy)/(dx)=(y^(2)+2xy)/(2x^(2)) , it is given that at x=1 , y=2 .

Solve the following differential equations (dy)/(dx)=(y^(2)+2xy)/(2x^(2)) , it is given that at x=1 , y=2 .

Solve the differential equations (i) (dy)/(dx)+(3xy+y^(2))/(x^(2)+xy)=0

Solve the differential equations (i) (dy)/(dx)+(3xy+y^(2))/(x^(2)+xy)=0

On putting (y)/(x)=v the differential equation (dy)/(dx)=(2xy-y^(2))/(2xy-x^(2)) is transferred to

The function y=f(x) is the solution of the differential equation (dy)/(dx)=(2xy+y^(2))/(2x^(2)) If f(1)=2, then the value of f((1)/(4)) is