Home
Class 12
MATHS
The equation of the image of the circle ...

The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the line mirror `4x+7y+13=0` is :

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the image ofthe circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is

The equatioin of the image of the circle x^(2)+y^(2)+016x-24y+183=0 in the line mirror 4x+7y+13=0 is: a.x^(2)+y^(2)+32x-4y+235=0 b.x^(2)+y^(2)+32x-4y-235=0cx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x+4y+235=0

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the line mirror x+y-1=0 is

Find the equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the line mirror x+y-1=0

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 in the mirror 4x+7y+13=0 is x^(2)+y^(2)+32x-4y+235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x-4y-235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x+4y+235=0

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

Find the equation of the image of the circle x^2+y^2+8x-16y+64=0 in the line mirror x=0.

Find the equation of the image of the circle x^(2)+y^(2)+8x-16+64=0 in the line mirror x=0.

Find the equation of the image of the circle : x^2 + y^2 + 8x-16y + 64=0 in the mirror x = 0.

Find the image of the circle x^2+y^2-2x+4y-4=0 in the line 2x-3y+5=0