" (iv) "ax+by=1,bx+ay=(2ab)/(a^(2)+b^(2))

Solve the following simultaneous linear equations in two linear variables by the method of cross-multiplication : ax+by=1, bx+ay=(2ab)/(a^(2)+b^(2))

Solve for x and y: ax+by=1" and "bx+ay=(2ab)/(a^(2)+b^(2)) .

If ax+by=1 and bx+ay=(2ab)/(a^(2)+b^(2)) then (x^(2)+y^(2))(a^(2)+b^(2)) is equal to

Solve the following system of equations in x and yax+by=1bx+ay=((a+b)^(2))/(a^(2)+b^(2))-1 or,bx+ay=(2ab)/(a^(2)+b^(2))

Solve by the method of substitution: ax+by=1, bx+ay=(a+b)^2/(a^2+b^2)-1

ax+by=a-b;bx-ay=a+b

ax+by=2; bx+ay=3

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}