A focal chord SE of the parabola `y^(2) = 8x` passes through the end point, having positive coordinates, of another chord `EF' : x = 4 ` . Find the equation and the length of the chord .

PP' is a focal chord of the parabola y^(2)=8x . If the coordinates of P are (18,12), find the coordinates of P'

The length of the chord of the parabola x^(2) = 4 y passing through the vertex and having slops cot alpha is

The length of the chord of the parabola x^(2) = 4y passing through the vertex and having slope cot alpha is

If athe coordinates of one end of a focal chord of the parabola y^(2) = 4ax be (at^(2) ,2at) , show that the coordinates of the other end point are ((a)/(t^(2)),(2a)/(t)) and the length of the chord is a(t+(1)/(t))^(2)

The length of the chord of the parabola y^(2)=x are ends of the chord Mid point (2,1) is

The focal chord of the parabola y^(2)=ax is 2x-y-8=0. Then find the equation of the directrix.

The focal chord of the parabola y^2=a x is 2x-y-8=0 . Then find the equation of the directrix.

The focal chord of the parabola y^2=a x is 2x-y-8=0 . Then find the equation of the directrix.

The focal chord of the parabola y^2=a x is 2x-y-8=0 . Then find the equation of the directrix.