[" If the latus rectum of the ellipse "],[x^(2)tan^(2)alpha+y^(2)sec^(2)alpha=1" is "(1)/(2)" then "alpha=],[(pi)/(12)],[(pi)/(6)],[(5 pi)/(12)],[(pi)/(3)]

If latus recturn of the ellipse x^(2)tan^(2)alpha+y^(2)sec^(2)alpha=1 is (1)/(2) then alpha(0

If latus recturn of the ellipse x^2 tan^2 alpha+y^2 sec^2 alpha= 1 is 1/2 then alpha(0 lt alpha lt pi) is equal to

If latus recturn of the ellipse x^2 tan^2 alpha+y^2 sec^2 alpha= 1 is 1/2 then alpha(0 lt alpha lt pi) is equal to

If 0 lt alpha lt (pi)/(2) and the eccentricity of the ellipse x^(2) tan^(2) alpha + y^(2) sec^(2) alpha = 1 is 1//2 , then alpha

If latus rectum of ellipse x^2 tan^2 phi + y^2 sec^2 phi = 1 is 1/2 , then (0ltphi ltpi) is equal to (A) pi/2 (B) pi/6 (C) pi/3 (D) pi/12

If the eccentricity of the hyperbola x^(2)-y^(2)sec^(2)alpha=5 is sqrt(3) xx the eccentricity the ellipse x^(2)sec^(2)alpha+y^(2)=25 then alpha=(pi)/(6) b.(pi)/(4) c.(pi)/(3) d.(pi)/(2)

If the eccentricity of the hyperbola x^(2)-y^(2)(sec)alpha=5 is sqrt(3) xx the eccentricity of the ellipse x^(2)(sec)^(2)alpha+y^(2)=25, then a value of alpha is : (a) (pi)/(6) (b) (pi)/(4) (c) (pi)/(3) (d) (pi)/(2)

If (1+tan alpha)(1+tan4 alpha)=2,alpha in(0,(pi)/(16)) then alpha is equal to (a) (pi)/(20) (b) (pi)/(30) (c) (pi)/(40) (d) (pi)/(60)