(i)(sin A+sin B)/(cos A+cos B)=tan((A+B)/(2))

Prove that (sin A+sin B)/(cos A+cos B)=tan((A+B)/2)

Prove that: (sin A-sin B)/(cos A+cos B)=tan((A-B)/2)

Prove that: (sin A+sin B)/(cos A+cos B)=tan((A+B)/2)

Prove that (sin A-sin B)/(cos A+ cos B) = "tan" (A-B)/2

Prove the following identities: tan^(2)A-tan^(2)B=(cos^(2)B-cos^(2)A)/(cos^(2)B cos^(2)A)=(sin^(2)A-sin^(2)B)/(cos^(2)A cos^(2)B)(sin A-sin B)/(cos A+cos B)+(cos A-cos B)/(sin A+sin B)=0

If A and B are complementary angles,then sin A=sin B(b)cos A=cos B(c)tan A=tan B(d)sec A=cos ecB

If cos(A-B)=3/5 and tan A tan B=2, then (a) cos A cos B=1/5 (b) sin A sin B=-2/5 (c) cos A cos B=-1/5 (d) sin A sin B=-1/5

(sin ^ (2) A-sin ^ (2) B) / (sin A cos A-sin B cos B) = tan (A + B)

(sin A - sin B)/(cos A+ cos B) is equal to ................. A) sin ((A+B)/(2)) B) 2 tan (A+B) C) cot ((A-B)/(2)) D) tan ((A-B)/(2))

(sin^(2)A-sin^(2)B)/(sin A cos A-sin B cos B) is equal to (a) sin A cos A-sin B cos Btan(A-B)(b)tan(A+B)cot(A-B)(d)cot(A+B)