A photon of frequency `v` causes photo electric emission from a surface with threshold frequency `v_(0)`. The de-Broglies wavelength `(lambda)` of the photo electron emitted is given by:

A photon of frequency n causes photoelectric emmission from a surface with threshold frequency n_0 .The de Broglie wavelength lambda of the photoelectron emitted is given as

A photon of frequency n causes photoelectric emmission from a surfece with thereshold .The de Broglie wavelength lambda of the photoelectrn emitted is given as

Photons of frequency, v, fall on metal surface for which the threshold frequency is v_(0) . Then

A photon of frequency v is incident on a metal surface whose threshold frequency is v_(0) . The kinetic energy of the emitted photoelectrons will be

X-ray fall on a photosenstive surface to cause photoelectric emission. Assuming that the work function of the surface can be neglected, find the relation between the de -Broglie wavelength (lambda) of the electrons emitted to the energy (E_v) of the incident photons. Draw the nature of the graph for lambda as a function of E_v .

X-rays fall on a photosensitive surface to cause photoelectric emission. Assuming that the work function of the surface can be neglected, find the relation between the de-Broglie wavelength ( lambda ) of the electrons emitted to the energy ( E_(v) ) of the incident photons. Draw the nature of the graph for lambda as a function of E_(v) .

Light of frequency v is incident on a substance of threshold frequency v(v lt v) . The energy of the emitted photo-electron will be