`dy/dx` ज्ञात कीजिए, जबकि -
`x=sint,y=cos2t`

dy/dx का मान ज्ञात कीजिए यदि x=2at,y=at^2

Find (dy)/(dx),x=sint,y=cos2t

Find dy/dx , if x = 6(t-sint) , y= 4(1-cost)

Find dy/dx , If x=a(t-sint) , y=a(1+cost)

Find (dy)/(dx) , if x=a(t-sint), y=a(1-cost)at t=(pi)/2

Find dy/dx , if x = a sint , y = a(cost + log (tan (t/2))

Find (dy)/(dx) when : x=a(2t+sin2t), y=a(1-cos2t)

Find (dy)/(dx) if x =a (t-sint),y=a(1-cos t)?

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=sint , y=cos2t