Seven year ago, Varun's age was five times the square of swati's age. Three years hence Swati's age will be two fifth of Varun's age. Find their present ages.

Seven years ago Varun’s age was five times the square of Swati’s age. Three years hence Swati’s age will be two fifth of Varun’s age. Find their present ages.

Seven years ago Varuns age was five xx the square of Swatis age.Three years hence Swatis age will be two fifth of Varuns age.Find their present ages.

The sum of two numbers is 15. If the sum of their reciprocals is 3/10 . Find the numbers. Or Seven years ago keshav's age was five times the square of Raghav's age. Three years hence Raghav's age will be two fifth of Keshav's age. Find their present ages.

7 years ago Alka's age was 5 times the square of Swati's age. Three years hence Swati's age will be 2/5 th of Alka's age. Find their present ages.

The present age of Varun is 10 more than square of Swati's age. Five years hence Swati's age will be one-fourth of Varun's age. Find their present ages.

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages.

Five years ago, A's age was four times the age of B. Five years hence , A's age will be twice the age of B. Find their present ages.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Write their present ages.

10 years ago, the age of a father was four times the age of his son then. 10 years hence, the age of the father will be twice the age of his son. Find their present ages.