Home
Class 13
PHYSICS
[" (5) The equation of motion of project...

[" (5) The equation of motion of projection is "y=12x-(3)/(4)x^(2)" The horizotal componet of velocity is "3],[ms'" .What iw the range of the projecitle? "],[[" (a) ",18" m "," (b) "quad 16m," (c) "12m," (d) "21.6m]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

" f the equation of motion of a proje-ctiel is "y=3x-(1)/(8)x^(2)," the range and maximum height are respectively "(y" and "x" are in metres) "

For ground to ground projectile motion equation of path is y=12x-3//4x^(2) . Given that g=10ms^(-2) . What is the range of the projectile ?

For ground to ground projectile motion equation of path is y=12x-3//4x^(2) . Given that g=10ms^(-2) . What is the range of the projectile ?

If the equation of motion of a projectile is y=3x -1/8 x^(2) the range and maximum height are respectively (y and x are in metres)

If the equation of motion of a projectile is y=3x -1/8 x^(2) the range and maximum height are respectively (y and x are in metres)

If the equation of motion of a projectile is y = 3x -1/8 x^(2) , the range and maximum height are respectively (y and x are in metres).