" ) "|[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]|=0

Prove the following : [[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]] =0

det[[1,bc,bc(b+c)1,ca,ca(c+a)1,ab,ab(a+b)]]=0

|(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b))|=

What is the value of the determinant |(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b))| ?

Without expanding,show that the following determinant vanishes. abs ((1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b)))

Without expanding show that : |(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b))|=0

Prove that . |[1,a,a^2-bc],[1,b,b^2-ca],[1,c,c^2-ab]|=0

Prove that |[1,a,a^2-bc],[1,b,b^2-ca],[1,c,c^2-ab]|= 0

|{:(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b)):}|=0