if `3sinx+4cosx=5,` then `4sinx-3cosx` is

int dx/(3sinx + 4cosx)

intdx/(3sinx-4cosx+5)

intdx/(3sinx-4cosx+5)

If 3sinx + 4cosx = 2, then the value of 3cosx - 4 sinx is equal to: यदि 3sinx + 4cosx = 2 तो 3cosx - 4sinx का मान ज्ञात करें:

If 3sinx+4cosx=2 , then find the value of 3cosx-4sinx .

The value of 3(sinx - cosx)^4 + 6(sinx + cosx)^2 + 4 (sin^6 x + cos^6 x) is

The number of distinct real roots of the equation |{:(cosx, sinx, sinx), (sinx, cosx, sinx), (sinx, sinx, cosx):}|=0 in the interval [-\ pi/4,pi/4] is- a. 3 b. \ 4 c. \ 2 d. 1

Show that, sin3x + cos3x = (cosx-sinx)(1+4sinx cosx)

Show that, sin3x + cos3x = (cosx-sinx)(1+4sinx cosx)