Two balls are projected upward simultaneously with speeds 40 m/s and 60 m/s. Relative position (x) of second ball w.r.t. first ball at time t = 5 s is [Neglect air resistance].

Two balls are projected vertically upward with same speed 35 m/s in 3s interval. Find height at which both balls collide.

A ball is projected from top of the table with initial speed u at an angle of inclination theta , motion of image of ball w.r.t ball

A ball is projected from top of the table with initial speed u at an angle of inclination theta , motion of image of ball w.r.t ball

A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take g=9.8m/s^(2) and neglect of air resistance]:-

A ball is projected vertically upward with a speed of 50 m/s. Find the time to reach the maximum height,

A ball projected from ground vertically upward is at same height at time t_(1) and t_(2) . The speed of projection of ball is [Neglect the effect of air resistance ]

A player throws a ball upward with an initial speed of 29.4 m//s .After how long does the ball return to the player’s hand, (g = 9.8 m//s^2,neglect air resistance)

Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .

Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .