If `(20)!``=k*(2^(a)3^(b)5^(c))` (where `a,b,c in N`, k does not contain any factor of 2, 3 and 5) then `a+b+c=`

If (500)! =k*(2^(a)3^(b)5^(c)) (where a,b,c in N , k does not contain any factor of 2, 3 and 5) then (A) agtc (B) c=124 (C) number of zeros at the end of (500)! is equal to 124 (D) (500)! is an even number

If sum_(k = 1)^(oo) (1)/((k + 2)sqrt(k) + ksqrt(k + 2)) = (sqrt(a) + sqrt(b))/(sqrt(c)) , where a, b, c in N and a,b,c in [1, 15] , then a + b + c is equal to

if sum_(k+1)(k)/(k+1)*^(100)C_(k)=(a*2^(100)+b)/(c) where a,b,c in N then find the least value of a+b+c

The value of ((2^(a))^(b c))/((5^(b))^( a c)) , where a = 2, b = 3, and c = 0, is

factorize : (3a+5b)^2-4c^2

If a^(2)+b^(2)+c^(2)=1 where, a,b, cin R , then the maximum value of (4a-3b)^(2) + (5b-4c)^(2)+(3c-5a)^(2) is

If (a^(2)+c^(2))/(a+c)=(b^(2)+c^(2))/(b+c)=k then value of k could be

If log ((5c)/(a)) , log ((3b)/(5c)) and log ((a)/(3b)) are n an A.P., where a, b and c are in a GP, then a, b and c, are the lengths of sides of