An object of mass 2kg is released at origin of x -y plane ,where its potential energy changes as U=(2x-4y) joules. Find speed of object after 3sec of release ,use sqrt(5)=2.24)

An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy ? If the object is allowed to fall, find its kinetic energy when it is half - way down.

A particle is released from rest at origin.It moves under influence of potential energy U=(x^(2)-3x) ,the kinetic energy at x=2m is

A particle of mass 4 kg moves along x axis, potential energy ( U ) varies with respect to x as U = 20 + ( x-4)^(2) , maximum speed of paritcle is at

A particle of mass 5kg moving in the X-Y plane has its potential energy given by U=(-7x+24y) J . The particle is initially at origin and has a velocity vec(U)=(14.4+4.2J)m//s

A particle of mass 2 kg moving along x-axis has potential energy given by, U=16x^(2)-32x ( in joule), where x is in metre. Its speed when passing through x=1 is 2ms^(-1)

If the potential energy of a harmonic oscillator of mass 2kg on its equilbrium position is 5 joules and the total energy is 9 joules when the amplitude is one meter the period of the oscillator ("in" sec) is-

An object of mass 5 kg is projected with a velocity of 20 m/s at angle of 60° to the horizontal. At the highest point of its path, the projectile explodes and breaks up into two fragments of masses 1 kg and 4 kg. The fragments separate horizontally after the explosion. The explosion releases internal energy such that the kinetic energy of the system at the highest point is doubled. If the separation between the two fragments when they reach the ground is x, then find the value of x/(5sqrt(3)) .

On an object of mass 1 kg moving along x-axis with constant speed 8 m/s, a constant force 2 N is applied in positive y-direction. Find its speed after 4 seconds.

An object is moving in x-y plane its velocity and acceleration at t=0 are represented in figure. After how much time object crosses the y- axis:-