Let "P" ,"Q" be points of the ellipse "`16x^(2)+25y^(2)=400`" ,so that "`PQ=96/25`" and "P" ,"Q" lie above major axis. The circle drawn with "PQ" as diameter touches major axis at positive focus .If "m" is slope of "PQ" then the value of "`1/|m|`" is

Let P and Q be points of the ellipse 16 x^(2) +25y^(2) = 400 so that PQ = 96//25 and P and Q lie above major axis. Circle drawn with PQ as diameter touch major axis at positive focus, then the value of slope m of PQ is

The tangent at any point on the ellipse 16x^(2)+25y^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through

The tangent at any point on the ellipse 16x^(2) + 25^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through

Co-ordinates of a point P((pi)/(3)) on the ellipse 16x^(2) + 25y^(2) = 400 are

The line x=2y intersects the ellipse (x^(2))/4+y^(2)=1 at the points P and Q . The equation of the circle with PQ as diameter is

A focal chord perpendicular to major axis of the ellipse 9x^(2)+5y^(2)=45 cuts the curve at P and Q then length of PQ is

If 'P' be a moving point on the ellipse (x^(2))/(25)+(y^(2))/(16)=1 in such a way that tangent at 'P' intersect x=(25)/(3) at Q then circle on PQ as diameter passes through a fixed point.Find that fixed point.

A ray emanating from point A(-3,0) incidents at the point P on the surface of the ellipse 16x^(2)+25y^(2)=400 and get reflected parallel to minor axis of the ellipse and again reflected at point Q on the surface of the ellipse,then area of Delta APQ lies in

The tangent at any point P on y^(2)=4x meets x-axis at Q, then locus of mid point of PQ will be