If `theta` is the angle between unit vectors `vecA` and `vecB`, then `((1-vecA.vecB))/((1+vecA.vecB))` is equal to

The angle between vectors (vecA xx vecB) and (vecB xx vecA) is :

If theta is the angle between unit vectors veca and vecb then sin(theta/2) is (A) 1/2|veca-vecb| (B) 1/2|veca+vecb| (C) 1/2|vecaxxvecb| (D) 1/sqrt(2)sqrt(1-veca.vecb)

If the angle between the vectors vecA and vecB is theta, the value of the product (vecB xx vecA) * vecA is equal to

If theta is the angle between the unit vectors veca and vecb , then prove that i. cos((theta)/2)=1/2|veca+vecb| ii. sin (theta/2)=1/2|veca-vecb|

If theta is the angle between the unit vectors veca and vecb , then prove that i. cos((theta)/2)=1/2|veca+vecb| ii. sin (theta/2)=1/2|veca-vecb|

If |veca|=|vecb| , then (veca+vecb).(veca-vecb) is equal to

Assertion: If theta be the angle between vecA and vecB then tan theta=(vecAxxvecB)/(vecA.vecB) Reason: vecAxxvecB is perpendicular to vecA.vecB

Find the angle between unit vector veca and vecb so that sqrt(3) veca - vecb is also a unit vector.

If veca and vecb are two unit vectors and the angle between them is 60^(@) then ((1+veca.vecb))/((1-veca.vecb)) is