The component of `vecA` along `vecB` is `sqrt(3)` times that of the component of `vecB` along `vecA`. Then A:B is

If vec2hati+3hatj and vecB=2hatj+3hatk the component of vecB along vecA is

If vecA=5hati-2hatj+3hatk and vecB=2hati+hatj+2hatk , component of vecB along vecA is

If veca=4hati+6hatj and vecb=3hati+4hatk find the vector component of veca alond vecb .

vecA and vecB are two vectors gives by vecA = 2 hati + 3hatj and vecB = hati +hatj . The magnetiude of the component of vecA along vecB is :

Let |A|=1, |vecb|=4 and veca xxvecr +vecb=vecr . If the projection of vecr along veca is 2, then the projection of vecr along vecb is

There are two vectors vecA=3hati+hatj and vecB=hatj+2hatk . For these two vectors- (a) Find the component of vecA along vecB in vector form. (b) If vecA & vecB are the adjacent sides of a parallalogram then find the magnitude of its area. (c) Find a unit vector which is perpendicular to both vecA & vecB .

Let veca, vecb and vecc be three vectors such that |veca|=2, |vecb|=1 and |vecc|=3. If the projection of vecb along veca is double of the projection of vecc along veca and vecb, vecc are perpendicular to each other, then the value of (|veca-vecb+2vecc|^(2))/(2) is equal to

If |vecA xx vecB| = sqrt(3) vecA .vecB then the value of |vecA xx vecB| is :

Vector veca is prepedicular to vecb , componets of veca- vecb along veca + vecb will be :

If |vecA xx vecB| = sqrt3 vecA *vecB , then the value of |vecA + vecB| is :